Ex 4.1, 2 - 13 + 23 + 33 + .. + n3 = (n(n + 1)/2)2 by induction - Ex 4.1

Ex 4.1, 2 - Chapter 4 Class 11 Mathematical Induction - Part 2
   Ex 4.1, 2 - Chapter 4 Class 11 Mathematical Induction - Part 3

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Question2: Prove the following by using the principle of mathematical induction 13 + 23 + 33+ + n3 = ( ( +1)/2)^2 Let P (n) : 13 + 23 + 33 + 43 + ..+ n3 = ( ( +1)/2)^2 For n = 1, L.H.S = 13 = 1 R.H.S = (1(1 + 1)/2)^2= ((1 2)/2)^2= (1)2 = 1 Hence, L.H.S. = R.H.S P(n) is true for n = 1 Assume that P(k) is true 13 + 23 + 33 + 43 + ..+ k3 = ( ( + 1)/2)^2 We will prove that P(k + 1) is true. 13 + 23 + 33 + ..+ k3 + (k + 1)3= ((k + 1)((k + 1)+ 1)/2)^2 13 + 23 + 33 + ..+ k3 + (k + 1)3= ((k + 1)( + 2)/2)^2 We have to prove P(k+1) from P(k) i.e. (2) from (1) From (1) 13 + 23 + 33 + 43 + ..+ k3 = ( ( + 1)/2)^2 Adding (k+1)3 both sides, 13 + 23 + 33 + ..+ k3 + (k + 1)3 = ( ( + 1)/2)^2+ (k + 1)3 = ( ^2 ( + 1)^2)/2^2 + (k + 1)3 = ( ^2 ( + 1)^2)/4 + (k + 1)3 = (k^2 (k + 1)^2 + 4( + 1)^3)/4 = ((k + 1)^2 (k^2 + 4 + 4))/4 = ((k + 1)^2 (k^2 + 2 + 2 + 4))/4 = ((k + 1)^2 ( ( + 2) + 2( + 2)))/4 = ((k + 1)^2 (( + 2) ( + 2)))/4 = ((k + 1)^2 (k + 2)^2)/4 = ((k + 1)( + 2)/2)^2 Thus, 13 + 23 + 33 + ..+ k3 + (k + 1)3= ((k + 1)( + 2)/2)^2 i.e. P(k + 1) is true whenever P(k) is true By the principle of mathematical induction, P(n) is true for n, where n is a natural number

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo