In what direction is the ring getting pulled?

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To find direction, we need to find Resultant force Now, Resultant force exerted by teams (𝑭 ⃗) = 𝑎 ⃗+𝑏 ⃗+𝑐 ⃗ = −𝒊 ˆ + 𝒋 ˆ This is in direction of 𝒃 ⃗ . Finding angle of vector 𝒃 ⃗ with respect to x-axis Now, Resultant force (𝑭 ⃗) = −𝒊 ˆ + 𝒋 ˆ And, Vector of x-axis = 𝑥 ⃗ = 𝒊 ˆ Now, 𝐹 ⃗.𝑥 ⃗=|𝐹 ⃗ ||𝑥 ⃗ | cos⁡〖𝜃 〗 (−𝒊 ˆ + 𝒋 ˆ) . 𝒊 ˆ = √𝟐 × 1 × cos θ −1 = √2 × cos θ (−1)/√2 = cos θ cos θ = (−𝟏)/√𝟐 Since cos is negative ∴ Angle is in second quadrant And, cos 𝝅/𝟒 = 𝟏/√𝟐 Therefore, Required angle = 𝜋 − 𝜋/4 = 𝟑𝝅/𝟒

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo