CBSE Class 12 Sample Paper for 2024 Boards

CBSE Class 12 Sample Paper for 2023 Boards →
Class 12
Solutions of Sample Papers and Past Year Papers - for Class 12 Boards

Question 27 - CBSE Class 12 Sample Paper for 2024 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards

Last updated at April 16, 2024 by

The random variable X   has a probability distribution P ( X ) of the following form, where  ' k ' is some real number:

P(X) = {k , if x = 0, 2k , if x = 1, 3k , if x = 2, 0 otherwise

(i) Determine the value of k.

(ii) Find P (X<2)

(iii)Find P (X>2)

This question is similar to Question 9 Chapter 13 Class 12

Slide10.JPG

Slide11.JPG
Slide12.JPG
Slide13.JPG

 

Go Ad-free

Transcript

(i) Find k Since X is a random variable , its Sum of Probabilities is equal to 1 P(X = 0) + P(X = 1) + P(X = 2) = 1 k + 2k + 3k = 1 6k = 1 k = 𝟏/𝟔 Our probability distribution table is P(X < 2) = P(X = 0) + P(X = 1) = k + 2k = 3k = 3 × 𝟏/𝟔 = 𝟏/𝟐 (iii) Find P (X > 2) Given 𝑃(𝑋)={■(𝑘," if " 𝑥=0@2𝑘," if " 𝑥=1@3𝑘," if " 𝑥=2@█(0," otherwise" @" " ))┤ For value of X other than 0, 1 and 2, the P(X) = 0 P(X > 2) = P(X = 3) + P(X = 4) + …… = 0 + 0 + ….. = 0

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo