Question 21 (Choice 1) - CBSE Class 12 Sample Paper for 2024 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards

Last updated at Dec. 13, 2024 by Teachoo

Find the value of 〖sin〗^(-1) [cos(33π/5)]

This question is similar to Example-9 Chapter-2 Inverse trigonometry

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Transcript

sin−1 ("cos " 33π/6) = sin−1 ("cos " (𝟔𝝅+𝟑𝝅/𝟓)) = sin−1 ("cos " 3𝜋/5) = sin−1 ("sin" (𝝅/𝟐 −𝟑𝛑/𝟓)) = sin−1 ("sin" ((5𝜋 − 6𝜋)/10 )) = sin−1 ("sin" ((−𝝅)/𝟏𝟎 )) Let y = sin−1 ("sin" ((−𝜋)/10 )) sin y = "sin" ((−𝜋)/10 ) sin y = sin (-18°) Hence, y = (−𝝅)/𝟏𝟎 Which is in the range of sin-1 i.e. [(−𝛑)/𝟐, 𝛑/𝟐] Hence, 〖𝒔𝒊𝒏〗^(−𝟏) [𝒄𝒐𝒔(𝟑𝟑𝝅/𝟔)] = (−𝝅)/𝟏𝟎 Hence, 〖𝒔𝒊𝒏〗^(−𝟏) [𝒄𝒐𝒔(𝟑𝟑𝝅/𝟔)] = (−𝝅)/𝟏𝟎

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo

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