CBSE Class 10 Sample Paper for 2024 Boards - Maths Standard

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Question 38 (ii) (Choice 1) - CBSE Class 10 Sample Paper for 2024 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards

Last updated at April 16, 2024 by

How far did the bird fly in the mentioned time?

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Distance travelled by bird is AD Now, AD = BE = CE – CB = CE βˆ’ 80 ∴ We need to find CE In right angle triangle DEC tan C = (𝑆𝑖𝑑𝑒 π‘œπ‘π‘π‘œπ‘ π‘–π‘‘π‘’ π‘‘π‘œ π‘Žπ‘›π‘”π‘™π‘’" " 𝐢)/(𝑆𝑖𝑑𝑒 π‘Žπ‘‘π‘—π‘Žπ‘π‘’π‘›π‘‘ π‘‘π‘œ π‘Žπ‘›π‘”π‘™π‘’" " 𝐢) tan C = (" " 𝐷𝐸)/𝐢𝐸 tan 30Β° = πŸ–πŸŽ/π‘ͺ𝑬 1/√3 = 80/𝐢𝐸 CE = 80βˆšπŸ‘ m Thus, AD = CE – CB = 80 √3 βˆ’ 80 = 80(βˆšπŸ‘ βˆ’ 1) m

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo