Example 12 - Chapter 3 Class 11 Trigonometric Functions

Last updated at Dec. 16, 2024 by

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Example 12 Find the value of tan 13πœ‹/12 tan (13 πœ‹" " )/12 = tan ("Ο€ + " 𝝅/𝟏𝟐) = tan 𝝅/𝟏𝟐 = 𝒕𝒂𝒏 (𝝅/πŸ’βˆ’π…/πŸ”) Using tan (π‘₯ – 𝑦) = (tanπ‘₯ βˆ’ tan⁑y)/(1 + tan π‘₯ tan⁑y ) = (tan⁑〖 Ο€/4γ€— βˆ’ tan Ο€/6)/(1 + tan Ο€/4 tan⁑〖 Ο€/6γ€— ) = (𝟏 βˆ’ 𝟏/βˆšπŸ‘)/(𝟏 + 𝟏/( βˆšπŸ‘)) = (βˆšπŸ‘ βˆ’ 𝟏)/(βˆšπŸ‘ + 𝟏) = (√3 βˆ’ 1)/(√3 + 1) Γ— (√3 βˆ’ 1)/(√3 βˆ’ 1) = (√(3 )βˆ’ 1)2/(√3 + 1)(√3 βˆ’ 1) = (3 + 1 βˆ’ 2√3)/((√3)2 βˆ’ (1)2) = (4 βˆ’ 2√3)/(3 βˆ’ 1) = 2 – βˆšπŸ‘

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo