Example 10 - Chapter 3 Class 11 Trigonometric Functions

Last updated at Dec. 16, 2024 by

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Example 10 Prove that 3sin "π " /6 sec "π " /3 – 4 sin "5π " /6 cot "π " /4 = 1 Solving LHS 3sin "π " /6 sec "π " /3 – 4 sin "5π " /6 cot "π " /4 = 3 × 𝟏/𝟐 × 2 – 4 sin (𝝅 −𝝅/𝟔) × 1 = 3 – 4 sin 𝝅/𝟔 = 3 – 4 × "1 " /2 = 1 = R.H.S.

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo