Example 5 - Chapter 3 Class 11 Trigonometric Functions
Last updated at April 16, 2024 by Teachoo
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Chapter 3 Class 11 Trigonometric Functions
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Transcript
Example 5 If the arcs of the same lengths in two circles subtend angles 65° and 110° at the center, find the ratio of their radii. We know that 𝑙 = r θ Let the radius of the two circles be r1 and r2 Length of arc of 1st Circle 𝑙 = r1 θ = r1 × 65° Converting into radians = r1 × 65° × 𝜋/(180°) = r1 × 𝟏𝟑𝝅/𝟑𝟔 Length of arc of 2nd circle 𝑙 = r2 θ = r2 × 110° Converting into radians = r2 × 110° × 𝜋/(180°) = r2 × 𝟏𝟏𝝅/𝟏𝟖 Given that Length of 1st arc = length of 2nd arc r1 × 𝟏𝟑𝝅/𝟑𝟔 = r2 × 𝟏𝟏𝝅/𝟏𝟖 𝑟1/𝑟2 = 11𝜋/18 × 36/13𝜋 𝑟1/𝑟2 = 22𝜋/13𝜋 𝒓𝟏/𝒓𝟐 = 𝟐𝟐/𝟏𝟑 Hence, r1 : r2 = 22 : 13 So, Ratio of Radius = 22 : 13
