CBSE Class 10 Sample Paper for 2024 Boards - Maths Standard

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Question 23 - CBSE Class 10 Sample Paper for 2024 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards

Last updated at Dec. 13, 2024 by

From an external point P, two tangents, PA and PB are drawn to a circle with centre O . At a point E on the circle, a tangent is drawn to intersect PA and PB at C and D, respectively. If PA = 10 cm, find the perimeter of ∆PCD

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Given PA = 10 cm We need to find perimeter of ∆PCD i.e. we need to find PC, PD and CD From Point A We know that Tangent from external point are equal ∴ PA = PB = 10 cm From Point C Since Tangent from external point are equal ∴ CA = CE From Point C Since Tangent from external point are equal ∴ DB = DE Now, Perimeter of ∆PCD = PC + PD + CD Putting CD = CE + ED = PC + PD + (CE + ED) Putting CE = AC, DE = DB = PC + PD + (AC + DB) = (PC + AC) + (PD + DB) = PA + PB = 10 + 10 = 20 cm

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