Question 1 - Principal and General Solutions - Chapter 3 Class 11 Trigonometric Functions

Last updated at Dec. 16, 2024 by

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Question 1 Find the principal and general solutions of the equation tan š‘„ = āˆš3 Given tan š‘„ = āˆš3 Principal Solution Principal solution is when 0 ā‰¤ x ā‰¤ 2šœ‹ We know that tan š›‘/šŸ‘ = āˆš3 & tan (šŸ’š›‘/šŸ‘) = tan (Ļ€" + " Ļ€/3) Therefore, the principal solutions are š‘„ = š›‘/šŸ‘ and šŸ’š›‘/šŸ‘ . General Solution Given tan š‘„ = āˆš3 tan š‘„ = tan Ļ€/3 āˆ“ š‘„ = nš›‘ + š›‘/šŸ‘, where n āˆˆ Z Therefore, the general solution is š‘„ = nĻ€ + Ļ€/3 , where n āˆˆ Z

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