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Ex 3.3, 22 Prove that cot 𝑥 cot 2𝑥 – cot 2𝑥 cot 3𝑥 – cot 3𝑥 cot 𝑥 = 1 Solving L.H.S. cot x cot 2x – cot 2x cot 3x – cot 3x cot x = cot x cot 2x – cot 3x (cot 2x + cot x) = cot x cot 2x – cot (2x + x) (cot 2x + cot x) = cot x cot 2x – ((cot 2x cot x − 1)/(cot x + cot 2x)) (cot 2x + cot x) = cot x cot 2x – (cot 2x cot x – 1) = cot x cot 2x – cot 2x cot x + 1 = 1 = R.H.S. Hence L.H.S = R.H.S Hence proved

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo