Ex 3.2, 9 - Chapter 3 Class 11 Trigonometric Functions

Last updated at Dec. 13, 2024 by Teachoo

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Ex 3.2,9 Find the value of the trigonometric function sin (–11"π" /3) sin ((−𝟏𝟏 𝝅)/𝟑) = –sin ((11 𝜋)/3) = –sin ("3 " 𝟐/𝟑 " π" ) = –sin ("4π – " 𝟏/𝟑 " π" ) = –sin ((−𝟏)/𝟑 " π" ) Rough So, 11/3 = 3 2/3 = 3 + 2/3 or 4 – 1/3 We take 4 – 𝟏/𝟑 as it is even = – ("–sin " (1/3 " π" )) = sin (𝟏/𝟑 " π" ) = sin 60° = √𝟑/𝟐

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo

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