(sec A + tan A) (1 – sin A) equals:

(a) sec A                        (b) sin A                   (c) cosec A               (d) cos A

This question is similar to Example 10 - Chapter 8 Class 10 Introduction to Trignometry

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Transcript

(sec A + tan A)(1 – sin A) We write everything in terms of sin A and cos A = (1/cos⁑〖 𝐴〗 +" " sin⁑〖 𝐴〗/cos⁑〖 𝐴〗 ) (1 – sin A) = ((1 +γ€– sin〗⁑〖 𝐴〗)/cos⁑〖 𝐴〗 )(1 – sin A) = ((1 +γ€– sin〗⁑〖 𝐴) (1 βˆ’γ€– sin〗⁑〖 𝐴)γ€— γ€—)/(cos⁑ 𝐴 ) = ((12 βˆ’γ€– sin^2〗⁑〖 𝐴) γ€—)/( cos⁑〖 𝐴〗 ) = ((𝟏 βˆ’γ€– γ€–π’”π’Šπ’γ€—^πŸγ€—β‘γ€– 𝑨) γ€—)/( 𝒄𝒐𝒔⁑〖 𝑨〗 ) = cos⁑〖2 𝐴〗/( cos⁑〖 𝐴〗 ) = cos A cos2 A + sin2 A = 1 cos2 A = 1 – sin2 A ∴ 1 – sin2 A = cos2 A So, the correct answer is (d)

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo