Given that sin θ = a/b, then cos θ is equal to
(A) b/√(b^2 - a^2 ) (B) b/a
(C) √(b^2 - a^2 )/b (D) a/√(b^2 - a^2 )
This question is exactly same as Question 7 - NCERT Exemplar - MCQ - Chapter 8 Class 10
Please check https://www.teachoo.com/13507/3604/Question-7/category/NCERT-Exemplar---MCQ/