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Ex 3.2, 2 Find the values of other five trigonometric functions if sin x = 3/5 , x lies in second quadrant. Since x is in llnd Quadrant sin will be positive But cos and tan will be negative Here , sin x = 3/5 We know that sin2x + cos2x = 1 (3/5)^2 + cos2x = 1 9/25 + cos2x = 1 cos2x = 1 – 9/25 cos2x = πŸπŸ”/πŸπŸ“ cos x = ±√(16/25) cos x = Β± πŸ’/πŸ“ As x is llnd Quadrant cos x is negative llnd Quadrant ∴ cos x = (βˆ’πŸ’)/πŸ“ Now, tan x = sin⁑π‘₯/cos⁑π‘₯ = (3/5)/(βˆ’ 4/5) = 3/5 Γ— 5/(βˆ’4) = (βˆ’πŸ‘)/πŸ’ cosec = 1/sin⁑π‘₯ = 1/(3/5) = πŸ“/πŸ‘ sec x = 1/cos⁑π‘₯ = 1/(βˆ’ 4/5) = (βˆ’πŸ“)/πŸ’ cot x = 1/tan⁑π‘₯ = 1/((βˆ’3)/4) = (βˆ’πŸ’)/πŸ‘

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo