Miscellaneous
Misc 2 (i)
Misc 2 (ii) Important
Misc 2 (iii) Important
Misc 2 (iv)
Misc 2 (v)
Misc 2 (vi) Important
Misc 3
Misc 4 Important
Misc 5
Misc 6 Important
Misc 7 Important
Misc 8
Misc 9
Misc 10 Important
Question 1
Question 2 Important You are here
Question 3 Important
Question 4
Question 5 Important
Question 6 Important
Last updated at April 16, 2024 by Teachoo
Question 2 Is it true that for any sets A and B, P (A) ∪ P (B) = P (A ∪ B)? Justify your answer. (If it is false, we take an example to prove it) Let A = {0, 1} and B = {1, 2} ∴ A ∪ B = {0, 1, 2} P(A ∪ B) = {∅, {0}, {1}, {2}, {0, 1}, {1, 2}, {0, 2}, {0, 1, 2} } ∴ P(A) ∪ P(B) ≠ P(A ∪ B) So, the given statement is False P(A) = {∅ , {0}, {1}, {0, 1}} P(B) = {∅, {1}, {2}, {1, 2}} P(A) ∪ P(B) = {∅, {0}, {1}, {0, 1}, {2}, {1, 2}}