Examples
Example 2 Important
Example 3
Example 4
Example 5 Important
Example 6 (i)
Example 6 (ii) Important
Example 6 (iii)
Example 6 (iv)
Example 6 (v)
Example 7 Important You are here
Example 8 (i)
Example 8 (ii)
Example 9 Important
Example 10
Example 11 Important
Example 12
Example 13 Important
Example 14
Example 15
Example 16
Example 17
Example 18 Important
Example 19
Example 20
Example 21
Example 22 Important
Example 23
Example 24 Important
Example 25
Question 1
Question 2 Important
Question 3 Important
Question 4
Question 5 Important
Question 6
Question 7 Important
Question 8 Important
Question 9 Important
Last updated at April 16, 2024 by Teachoo
Example 7 Find the pairs of equal sets, if any, give reasons: A = {0}, B = {x : x > 15 and x < 5}, C = {x : x – 5 = 0 }, D = {x: x2 = 25}, E = {x : x is an integral positive root of the equation x2 – 2x –15 = 0}. Let’s write all the sets in roster form A = {0} A = {0} B = {x : x > 15 and x < 5}, No number can be greater than 15 and less than 5 simultaneously. B = {} = Φ C = {x : x – 5 = 0} x – 5 = 0 , x = 5 . So, C = {5} D = {x: x2 = 25} x2 = 25 x = ±5 So, D = { +5, −5} E = {x : x is an integral positive root of the equation x2 – 2x –15 = 0}. x2 – 2x −15 =0 x2 – 5x + 3x – 15 =0 x(x – 5) + 3 (x – 5) = 0 (x − 5) (x + 3) = 0 x = 5 , −3 Since x is positive E = {5} Thus, A = {0} B = { } C = {5} D = { +5,-5} E = { 5} Therefore only C = E, as there elements are exactly the same