Ex 13.1, 3 - Chapter 14 Class 10 Statistics (Important Question)

Last updated at February 24, 2025 by

Ex 13.1, 3 - Daily pocket allowance of children of a locality - Ex 13.1

part 2 - Ex 13.1, 3 - Ex 13.1 - Serial order wise - Chapter 13 Class 10 Statistics
part 3 - Ex 13.1, 3 - Ex 13.1 - Serial order wise - Chapter 13 Class 10 Statistics

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Ex 13.1, 3 The following distribution shows the daily pocket allowance of children of a locality. The mean pocket allowance is Rs.18. Find the missing frequency f. Mean(š‘„ Ģ…) = a + (āˆ‘ā–’š’‡š’Šš’…š’Š)/(āˆ‘ā–’š’‡š’Š) Where a = Assumed Mean h = Class interval Putting values in formula Mean = 18 + (2š‘“ āˆ’ 40)/(44 + š‘“) 18 = 18 + (2š‘“ āˆ’ 40)/(44 + š‘“) 18 āˆ’ 18 = (2š‘“ āˆ’ 40)/(44 + š‘“) 0 = (2š‘“ āˆ’ 40)/(44 + š‘“) 0 = 2š‘“āˆ’40 2š‘“=40 f = 40/2 f = 20

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