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Ex 13.1, 3 The following distribution shows the daily pocket allowance of children of a locality. The mean pocket allowance is Rs.18. Find the missing frequency f. Mean(𝑥 ̅) = a + (∑▒𝒇𝒊𝒅𝒊)/(∑▒𝒇𝒊) Where a = Assumed Mean h = Class interval Putting values in formula Mean = 18 + (2𝑓 − 40)/(44 + 𝑓) 18 = 18 + (2𝑓 − 40)/(44 + 𝑓) 18 − 18 = (2𝑓 − 40)/(44 + 𝑓) 0 = (2𝑓 − 40)/(44 + 𝑓) 0 = 2𝑓−40 2𝑓=40 f = 40/2 f = 20

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo