Chemistry CBSE Class 12 Sample Paper for 2023 Boards - Solutions

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Solutions to CBSE Sample Paper - Chemistry Class 12

Question 19 - Chemistry CBSE Class 12 Sample Paper for 2023 Boards - Solutions - Solutions to CBSE Sample Paper - Chemistry Class 12

Last updated at April 16, 2024 by

A first-order reaction takes 69.3 min for 50% completion. What is the time needed for 80% of the reaction to get completed?

(Given: log 5 =0.6990, log 8 = 0.9030, log 2 = 0.3010)

 

Answer:

Half life t1/2 = 0.693 /k

k= 0.693/69.3 = 1/100 = 0.01 min -1

For first order reaction

π‘˜ = 2.303/𝑑 π‘™π‘œπ‘” [π‘…π‘œ]/[𝑅]

𝑑 = 2.303/0.01 π‘™π‘œπ‘” 100/20

𝑑 = 230.3 log 5 (log 5 =0.6990)

t= 160.9 min

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