What is the nuclear radius of 125 Fe ,if that of 27 Al is 3.6 fermi?.
Answer:
From the relation R = R 0 A 1/3 , where R 0 is a constant and A is the mass number of a nucleus
R Fe /R Al = (A Fe /A Al ) ⅓
= (125/27) ⅓
R Fe = 5/3 R Al
=5/3 x 3.6
= 6 fermi