Find the direction ratio and direction cosines of a line parallel to the line whose equations are 6š„ − 12 = 3š¦ + 9 = 2š§ − 2
CBSE Class 12 Sample Paper for 2023 Boards
CBSE Class 12 Sample Paper for 2023 Boards
Last updated at July 13, 2026 by Teachoo
Transcript
Question 23 (Choice 2) Find the direction ratio and direction cosines of a line parallel to the line whose equations are 6š„ ā 12 = 3š¦ + 9 = 2š§ ā 2 Given equation of line 6š„ ā 12 = 3š¦ + 9 = 2š§ ā 2 6(š„ ā 2) = 3(š¦ + 3) = 2(š§ ā 1) Dividing both sides by 6 (6(š„ ā 2))/6=(3(š¦ + 3))/6=(2(š§ ā 1))/6 ((š ā š))/š=((š + š))/š=((š ā š))/š Thus, Direction ratios of the line parallel to the line = 1, 2, 3 ā“ š = 1, b = 2, c = 3 Also, ā(š^š + š^š + š^š ) = ā(12 +22 +32) = ā(1 +4 +9) = āšš Direction cosines = š/ā(š^2 + š^2 + š^2 ) , š/ā(š^2 + š^2 + š^2 ) , š/ā(š^2 + š^2 + š^2 ) = š/āšš , š/āšš , š/āšš