The general solution of the differential equation π¦ππ₯ − π₯ππ¦ = 0 ππ
(a) π₯π¦ = πΆ
(b) π₯ = Cy 2
(c) π¦ = πΆπ₯
(d) π¦ = Cx 2
This question is Similar to Misc-16 - Class-12 Miscellaneous
CBSE Class 12 Sample Paper for 2023 Boards
CBSE Class 12 Sample Paper for 2023 Boards
Last updated at Dec. 13, 2024 by Teachoo
This question is Similar to Misc-16 - Class-12 Miscellaneous
Transcript
Question 15 The general solution of the differential equation π¦ππ₯ β π₯ππ¦ = 0 ππ (a) π₯π¦ = πΆ (b) π₯ = γπΆπ¦γ^2 (c) π¦ = πΆπ₯ (d) π¦ = Cπ₯^2π¦ ππ₯ β π₯ ππ¦=0 π¦ ππ₯= π₯ ππ¦ π π/π = π π/π Integrating both sides. β«1βγ(ππ₯ )/π₯=(ππ¦ )/(π¦ )γ log x = log y + C log x β log y = C log ((π )/π) = C (π )/π = c1 y = π₯/π_1 y = Cx So, the correct answer is (c)