Question 8 - Chapter 13 Class 10 Surface Areas and Volumes (Important Question)

Last updated at Dec. 13, 2024 by

Ex 13.3, 8 - Water in a canal, 6 m wide and 1.5 m deep - Ex 13.3

Ex 13.3, 8 - Chapter 13 Class 10 Surface Areas and Volumes - Part 2

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Question 8 Water in a canal, 6 m wide and 1.5 m deep, is flowing with a speed of 10 km/h. How much area will it irrigate in 30 minutes, if 8 cm of standing water is needed? Canal is the shape of cuboid where Breadth = 6 m Height = 1.5 m & Speed of canal = 10 km/hr Length of canal in 1 hour = 10 km Length of canal in 60 minutes = 10 km Length of canal in 1 min = 1/60 x 10 km Length of canal in 30 min = 30/60 10 = 5km = 5000 m Now, Volume of canal = Length Breadth Height = 5000 6 1.5 m3 Now Volume of water in canal = Volume of area irrigated Volume of water in canal = Area irrigated Height 5000 6 1.5 m3 = Area irrigated 8 cm 5000 6 1.5 m3 = Area irrigated 8/100 m (5000 6 1.5 100 )/8 = Area irrigated Area irrigated = 562500 m2 Area irrigated = 562500/10000 hectares Area irrigated = 56.25 hectares

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo