Two coins are tossed simultaneously. What is the probability of getting
(i) At least one head?
(ii) At most one tail?
(iii) A head and a tail?
This question is Similar to Question 6 - Past Year MCQ - Chapter 15 Class 10



CBSE Class 10 Sample Paper for 2023 Boards - Maths Standard
CBSE Class 10 Sample Paper for 2023 Boards - Maths Standard
Last updated at Dec. 13, 2024 by Teachoo
This question is Similar to Question 6 - Past Year MCQ - Chapter 15 Class 10
Transcript
Question 31 Two coins are tossed simultaneously. What is the probability of getting (i) At least one head? (ii) At most one tail? (iii) A head and a tail?When 2 coins are tossed Possible outcomes = HH, TH, HT, TT Letβs solve each part individually (i) At least one head? Now, Outcomes with atleast with 1 head = HH, HT, TH Thus, P(getting atleast 1 head) = (ππ’ππππ ππ ππ’π‘πππππ π€ππ‘β ππ‘ππππ π‘ 1 βπππ)/(πππ‘ππ ππ’ππππ ππ ππ’π‘πππππ ) = π/π(ii) At most one tail? Now, Outcomes with atmost with 1 tail = HH, HT, TH Thus, P(getting atmost 1 tail) = (ππ’ππππ ππ ππ’π‘πππππ π€ππ‘β ππ‘πππ π‘ 1 π‘πππ)/(πππ‘ππ ππ’ππππ ππ ππ’π‘πππππ ) = π/π (iii) A head and a tail? Now, Outcomes with a head and a tail = HT, TH Thus, P(getting with a head and a tail ) = (ππ’ππππ ππ ππ’π‘πππππ π€ππ‘β π βπππ πππ π π‘πππ)/(πππ‘ππ ππ’ππππ ππ ππ’π‘πππππ ) = 2/4 = π/π