CBSE Class 10 Sample Paper for 2023 Boards - Maths Standard

Practice Questions CBSE - Maths Class 10 (2023 Boards) →
Class 10
Solutions of Sample Papers for Class 10 Boards

Question 25 (Choice 2) - CBSE Class 10 Sample Paper for 2023 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards

Last updated at April 16, 2024 by

Find an acute angle θ when cos⁡θ - sin⁡θ/cos⁡θ  + sin⁡θ  = 1+ √3/1 + √3

Slide68.JPG

Slide69.JPG

 

Go Ad-free

Transcript

Question 25 (Choice 2) Find an acute angle θ when (cos⁡θ − sin⁡θ)/(cos⁡θ + sin⁡θ ) = (1 − √3)/(1 + √3)Given (cos⁡θ − sin⁡θ)/(cos⁡θ + sin⁡θ ) = (1 − √3)/(1 + √3) Cross multiplying (1 + √3) (cos θ − sin θ) = (1 − √3) (cos θ + sin θ) 1 (cos θ − sin θ) + √3(cos θ − sin θ) = 1 (cos θ + sin θ) − √3 (cos θ + sin θ) cos θ − sin θ + √3cos θ − √𝟑 sin θ = cos θ + sin θ − √3cos θ − √𝟑sin θ − sin θ + √3cos θ = sin θ − √3cos θ √3cos θ + √3cos θ = sin θ + sin θ 2√𝟑cos θ = 2 sin θ √3cos θ = sin θ √3 = sin⁡〖θ 〗/cos⁡〖θ 〗 tan θ = √3 Since tan 60° = (cos⁡θ − sin⁡θ)/(cos⁡θ + sin⁡θ ) = (1 − √3)/ So, the correct answer is (c) √3 = sin⁡〖θ 〗/cos⁡〖θ 〗 tan θ = √𝟑 Since tan 60° = √3 Therefore, θ = 60°

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo