Question 1 Let a and b be two positive integers such that a = p3q4 and b = p2q3, where p and q are prime numbers. If HCF(a,b) = pmqn and LCM(a,b) = prqs , then (m + n)(r + s) = (a) 15 (b) 30 (c) 35 (d) 72
Given two numbers
a = p3q4 and b = p2q3
Finding HCF
a = p3q4 = p × p × p × q × q × q × q
b = p2q3 = p × p × q × q × q
HCF = p × p × q × q × q
HCF = p2q3
Comparing HCF = p2q3 with HCF = pmqn
∴ m = 2, n = 3
Finding LCM
LCM = p × p × p × q × q × q × q
LCM = p3q4
Comparing LCM = p3q4 with LCM = prqs
∴ r = 3, s = 4
Now,
(m + n)(r + s) = (2 + 3) × (3 + 4)
= 5 × 7
= 35
So, the correct answer is (c)
Made by
Davneet Singh
Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo
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