Question 3 - Area of combination of figures : circle based - Chapter 11 Class 10 Areas related to Circles

Last updated at Dec. 13, 2024 by

Ex 12.3, 3 - If ABCD is a square of side 14 cm and APD - Area of combination of figures : circle based

Ex 12.3, 3 - Chapter 12 Class 10 Areas related to Circles - Part 2
Ex 12.3, 3 - Chapter 12 Class 10 Areas related to Circles - Part 3

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Transcript

Question 3 Find the area of the shaded region in figure, if ABCD is a square of side 14 cm and APD and BPC are semicircles. Area of shaded region = Area of square ABCD Area of semicircle APD Area of semicircle BPC Area of square ABCD Side of square = 14 cm Area of square = Side Side = 14 14 = 196 cm2 Area of semi circle APD Diameter = AD = 14 cm So, radius = /2 = 14/2 = 7 cm Area of semi circle APD = 1/2 r2 = 1/2 22/7 7^2 = 1/2 22/7 7 7 = 77 cm2 Similarly, For semicircle BPC Diameter = BC = 14 cm Since diameter is same Area of semi circle BPC = Area of semi circle APD = 77 cm2 Now, Area of shaded region = Area of square Area of semi circle APB Area of semi circle BPC = 196 77 77 = 196 (77 + 77) = 196 (154) = 42 cm2 Hence, area of shaded region = 42 cm2

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo