Verify the following using Boolean Laws: A + C = A + A’. C + B.C
Answer:
To prove: A + C = A + A’. C + B.C
Proof:
RHS
= A + A’. C + B.C
= (A+A’).(A+C) + B.C (using distributive law)
= 1.(A+C) + B.C (using complement law)
= A + C + (B.C) (using identity law)
= A + C.(1+B) (using distributive law)
= A + C.1 (using annulment law)
= A + C (using identity law)
= LHS
Hence, the expression A + C = A + A’. C + B.C is verified.