Question 2 (i) - Trignometric ratios of complementry angles - Chapter 8 Class 10 Introduction to Trignometry

Last updated at April 16, 2024 by

Ex 8.3, 2 - Show that (i) tan 48 tan 23 tan 42 tan 67 = 1 - Trignometric ratios of complementry angles

 

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Question 2 Show that : tan 48 tan 23 tan 42 tan 67 = 1 Taking L.H.S tan 48 tan 42 tan 23 tan 67 = tan 48 tan(90 48 ) tan 23 tan(90 23 ) = tan 48 cot 48 tan 23 cot 23 = (tan 48 1/tan 48 ) (tan 23 1/tan 23 ) = 1 1 = 1 = R.H.S L.H.S = R.H.S Hence proved

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo