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Question 1 (i) - Area of triangle - Chapter 7 Class 10 Coordinate Geometry
Last updated at Dec. 13, 2024 by Teachoo
Chapter 7 Class 10 Coordinate Geometry
Concept wise
- Distance Formula
- Equidistant points
- Checking points collinear or not
- Type of triangle formed
- Type of quadrilateral formed
- Section Formula- Finding coordinates
- Section Formula- Finding coordinates of a point in a quadrilateral
- Finding ratio
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Area of triangle
- Given area, finding k
- Area of quadrilateral
Transcript
Ex 7.3 , 1 Find the area of the triangle whose vertices are : (i) (2, 3), (–1, 0), (2, – 4) Let the two points be A(2, 3) , B(−1, 0) & C(2, −4) Area of triangle ABC = 1/2 [ x1(y2 – y3) + x2(y3 – y1) + x3(y1 – y2) ] Here x1 = 2 , y1 = 3 x2 = −1 , y2 = 0 x3 = 2 , y3 = −4 Putting values Area of triangle ABC = 1/2 [2(0 – (−4)) + (−1)(−4 – 3 ) + 2(3 – 0)] = 1/2 [ 2(4) + (−1)(– 7 ) + 2(3)] = 1/2 [8 + 7 + 6] = 1/2 [21] = 10.5 square units
