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Example 4 In figure, if PQ || RS, prove that Δ POQ ~ Δ SOR. Given: PQ II RS To Prove :- Δ POQ ~ Δ SOR Proof: In Δ POQ & Δ SOR ∠ POQ = ∠ SOR (Vertically Opposite Angles) ∠ P = ∠ S (AS PQ || RS, alternate angles) ∠ Q = ∠ R (AS PQ || RS, alternate angles) Using AAA similarity criterion Therefore , Δ POQ ~ Δ SOR Hence proved