An element ‘X’ has mass number 35 and 18 number of neutrons. Therefore, Electronic configuration of X= 2, 8, 7. Write atomic number and electronic configuration of ‘X’. Also write group number, period number and valency of ‘X’.

 

Answer

Mass number = 35

Number of neutrons = 18

  • Mass number = number of neutrons + number of protons

Therefore, number of protons = Mass number - number of neutrons

                                                      = 35 - 18 

                                                      = 17

  • Atomic number = number of protons = 17
  • Therefore, the electronic configuration of X is 2, 8, 7
  • Group number = 10 + number of valence electrons = 10 + 7 = 17
  • Since there are 3 shells, period number is 3.
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CA Maninder Singh is a Chartered Accountant for the past 14 years and a teacher from the past 18 years. He teaches Science, Economics, Accounting and English at Teachoo