Question 23 - Past Year - 3 Mark Questions - Chapter 4 Class 10 - Carbon and its Compounds

Last updated at April 16, 2024 by

An organic compound ‘P’ is a constituent of wine. ‘P’ on reacting with acidified K 2 Cr 2 O 7 forms another compound ‘Q’. When a piece of sodium is added to ‘Q’ a gas ‘R’ evolves which burns with a pop sound. Identify P, Q and R and write the chemical equations of the reactions involved.

 

Answer

  • P i.e. ethanol is a constituent of wine.
  • On reaction with K 2 Cr 2 O 7 which is an oxidizing agent, it forms ethanoic acid.

Reaction of Ethanol with Oxidizing Agent - Teachoo.png

  • Ethanoic acid reacts with NaOH which is a base to give sodium salt of ethanoic acid and water.

Reaction of Ethanoic acid with Sodium hydroxide - Teachoo.png

Thus,

  • P: Ethanol
  • Q: Ethanoic acid
  • R : Sodium salt of ethanoic acid  

 

Go Ad-free

Transcript

Reaction of Ethanoic acid with Sodium hydroxide CH3COOH Ethanoic acid NaOH Sodium hydroxide CH3COONa Sodium ethanoate H2O Water

Maninder Singh's photo - Co-founder, Teachoo

Made by

Maninder Singh

CA Maninder Singh is a Chartered Accountant for the past 14 years and a teacher from the past 18 years. He teaches Science, Economics, Accounting and English at Teachoo