Question 1 - Area of similar triangles - Chapter 6 Class 10 Triangles

Last updated at Dec. 13, 2024 by

Ex 6.4, 1 - Let ABC similar DEF and their areas be 64 cm2 - Area of similar triangles

Ex 6.4, 1 - Chapter 6 Class 10 Triangles - Part 2

Go Ad-free

Transcript

Question 1 Let ABC ~ DEF and their areas be, respectively, 64 cm2 and 121 cm2 . If EF = 15.4cm, find BC. Given:- ABC ~ DEF ar ABC = 64 cm2 ar DEF = 121 cm2 EF = 15.4 cm To find : BC Solution :- Since ABC ~ DEF We know that if two triangle are similar , Ratio of areas is equal to square of ratio of its corresponding sides Hence, ( )/( )=( / )^2 Putting the values 64/121=( /15.4)^2 64/121= 2/(15.4)2 64/121 (15.4)2= 2 ((8 8)/(11 11)) (15.4)2= 2 82/112 (15.4)2= 2 (8/11 15.4)2= 2 8/11 15.4= BC = 8/11 15.4 BC = 8 1.4 BC = 11.2 Hence, BC = 11.2 cm

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo