Ex 6.3, 15 - Chapter 6 Class 10 Triangles (Important Question)

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Ex 6.3, 15 - A vertical pole of length 6 m casts a shadow - AA Similarity

Ex 6.3, 15 - Chapter 6 Class 10 Triangles - Part 2

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Ex 6.3, 15 A vertical pole of length 6 m casts a shadow 4 m long on the ground and at the same time a tower casts a shadow 28 m long. Find the height of the tower. Given: Height of pole = AB = 6m Length of pole of shadow = BC = 4 m Length of shadow of tower = EF = 28 To Find : Height of tower i.e ED Solution:- In βˆ† 𝐴𝐡𝐢 and βˆ† 𝐷𝐸𝐹 ∠ B = ∠ E = 90Β° ∠𝐢=∠𝐹 ∴ βˆ† 𝐴𝐡𝐢 ∼ βˆ† 𝐷𝐸𝐹 βˆ† 𝐴𝐡𝐢 ∼ βˆ† 𝐷𝐸𝐹 We know that if two triangles are similar, ratio of their sides are in proportion So, 𝐴𝐡/𝐷𝐸=𝐡𝐢/𝐸𝐹 6/𝐷𝐸=4/28 6 Γ—28=𝐷𝐸×4 (6 Γ— 28)/4= 𝐷𝐸 6 Γ—7=𝐷𝐸 𝐷𝐸 = 42 Hence, the height of the tower is 42 metres

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