Following is the distribution of the long jump competition in which 250 students participated. Find the median distance jumped by the students. Interpret the median
This question is similar to Ex 14.3, 7 Chapter 14 Class 10 - Statistics
CBSE Class 10 Sample Paper for 2022 Boards - Maths Standard [Term 2]
Question 1 (Choice 2)
Question 2 Important
Question 3 Important
Question 4
Question 5 Important
Question 6 (Choice 1)
Question 6 (Choice 2)
Question 7 Important You are here
Question 8 Important
Question 9
Question 10 (Choice 1)
Question 10 (Choice 2)
Question 11 Important
Question 12 (Choice 1)
Question 12 (Choice 2)
Question 13 - Case Study Important
Question 14 - Case Study Important
CBSE Class 10 Sample Paper for 2022 Boards - Maths Standard [Term 2]
Last updated at April 16, 2024 by Teachoo
This question is similar to Ex 14.3, 7 Chapter 14 Class 10 - Statistics
Following is the distribution of the long jump competition in which 250 students participated. Find the median distance jumped by the students. Interpret the median Finding Median Median = l + (𝑁/2 −𝑐𝑓)/𝑓 × h Here, 𝑵/𝟐 ∴ 2 − 3 is median class And, l = h = cf = f = Putting values in formula Median = l + (𝑁/2 −𝑐𝑓)/𝑓 × h = 2 + (𝟏𝟐𝟓 −𝟏𝟐𝟎)/𝟔𝟐 × 1 = 2 + 5/62 = 2 + 0.0806 = 2.0806 Therefore, Median distance jumped by student is 2.0806 m By interpreting the median, We observe that 50% of students jump below 2.0806 m and 50% above it