Finding AP
Last updated at April 16, 2024 by Teachoo
Ex 5.2, 10 If 17th term of an A.P. exceeds its 10th term by 7. Find the common difference. We know that an = a + (n – 1) d So, a17 = a + (17 – 1) d a17 = a + 16d Also, a10 = a + (10 – 1)d a10 = a + 9d Given that 17th term of an A.P. exceeds its 10th term by 7 a17 – a10 = 7 (a + 16d) – (a + 9d) = 7 a + 16d – a – 9d = 7 a – a + 16d – 9d = 7 0 + 7d = 7 7d = 7 7d = 7 d = 7/7 d = 1 Therefore, common difference of the given AP is 1 (From (1) & (2))