f (x) = xx has a stationary point at

(A) x = e                      (B) x = 1/e

(C) x = 1                      (D) x = √e

f (x) = x^x has a stationary point at - Teachoo Class 12 [MCQ] - NCERT Exemplar - MCQs

part 2 - Question 16 - NCERT Exemplar - MCQs - Serial order wise - Chapter 6 Class 12 Application of Derivatives
part 3 - Question 16 - NCERT Exemplar - MCQs - Serial order wise - Chapter 6 Class 12 Application of Derivatives

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Question 16 f (x) = xx has a stationary point at (A) x = e (B) x = 1/š‘’ (C) x = 1 (D) x = āˆšš‘’ A stationary point of a function is a point where š’‡ā€²(š’™) = 0 For differentiating f (š‘„), we use logarithmic differentiation f (š‘„) = š‘„^š‘„ Taking log on both sides log f (š’™) = š’™ log š’™ Differentiating w.r.t. x 1/š‘“(š‘„) š‘“ā€²(š‘„) = š‘„ . 1/š‘„ + 1. log š‘„ 1/š‘„^š‘„ š‘“ā€²(š‘„) = 1 + log š‘„ š’‡ā€²(š’™) = š’™^š’™(1 + log š’™) Putting š’‡ā€™(x) = 0 š‘„^š‘„ ("1 + log " š‘„" " )=šŸŽ Either š’™^š’™ = 0 Since, š‘„^š‘„ is exponential function it can never be zero. Or 1 + log š’™ = 0 log š‘„ = āˆ’1 Taking exponential on both sides š’†^š’š’š’ˆā”š’™ = š’†^(āˆ’šŸ) š‘„ = š‘’^(āˆ’1) š’™ = šŸ/š’† Hence, Stationary point is š’™ = šŸ/š’† So, the correct answer is (B)

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