Question 9
The function f (x) = tan x – x
always increases
(B) always decreases
(C) never increases
(D) sometimes increases and sometimes decreases.
Given 𝑓(𝑥) = tan 𝑥 − 𝑥
Finding 𝒇^′ (𝒙)
𝑓^′ (𝑥)=〖𝒔𝒆𝒄〗^𝟐 𝒙 −𝟏
Now, we need to check if 𝒇(𝒙) is increasing or decreasing
Checking sign of 𝒇^′ (𝒙)
𝑓^′ (𝑥)=〖𝒔𝒆𝒄〗^𝟐 𝒙 −𝟏
Now,
𝐬𝐞𝐜 𝒙 𝝐 (−∞,−𝟏]∪[𝟏,∞)
So,
〖𝒔𝒆𝒄〗^𝟐 𝒙 𝜖 [1,∞)
Therefore, we can write this as
𝟏≤〖𝒔𝒆𝒄〗^𝟐 𝒙≤∞
1−𝟏≤〖𝑠𝑒𝑐〗^2 𝑥−𝟏≤∞−𝟏
0≤〖𝒔𝒆𝒄〗^𝟐 𝒙−𝟏≤∞
Thus,
〖𝑠𝑒𝑐〗^2 𝑥−1≥0
∴ 𝒇^′ (𝒙)>𝟎 for all values of x
Hence, 𝒇(𝒙) always increases.
So, the correct answer is (A)
Made by
Davneet Singh
Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo
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