Question 58 (Case Based MCQ) - Solutions - CBSE Class 10 Sample Paper for 2022 Boards - Science [MCQ] - Solutions to CBSE Sample Paper - Science Class 10
Last updated at April 16, 2024 by Teachoo
She measured the angles of incidence for both the rays on the left side of the box to be 48.6
°
. She knew the refractive index of the material ‘X’ inside the box was 1.5. What will be the approximate value of angle of refraction?
Question 58 She measured the angles of incidence for both the rays on the left side of the box to be 48.6° . She knew the refractive index of the material ‘X’ inside the box was 1.5. What will be the approximate value of angle of refraction? (A) 45° (B) 40° (C) 30° (D) 60° (use the value: sin 48.6° ≈ 0.75) Given,
Angle of incidence = i = 48.60
Angle of reflection = r = ?
We know that
Refractive index of any medium = sin𝑖/sin𝑟
1.5 = 𝐬𝐢𝐧〖𝟒𝟖.𝟔〗/𝐬𝐢𝐧𝒓
Putting sin 48.6° = 0.75
1.5 = 0.75/sin𝑟
sin r = 0.75/1.5
sin r = (75/100)/(15/10)
sin r = 75/100 × 10/15
sin r = 5/10
sin r = 𝟏/𝟐
Thus, r = 300
So, the correct answer is (C)
Made by
Maninder Singh
CA Maninder Singh is a Chartered Accountant for the past 14 years and a teacher from the past 18 years. He teaches Science, Economics, Accounting and English at Teachoo
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