Which among the following is(are) double displacement reaction(s)?
(i) Pb + CuCl 2 → PbCl 2 + Cu
(ii) Na 2 SO 4 + BaCl 2 → BaSO 4 + 2NaCl
(iii) C + O 2 → CO 2
(iv) CH 4 + 2O 2 → CO 2 + 2H 2 O
(A) (i) and (iv)
(B) (ii) only
(C) (i) and (ii)
(D) (iii) and (iv)
Answer
A double displacement reaction is the one in which the two reacting species exchange their ions .
Let’s look at all the options
- (i) is an example of a single displacement reaction as only one ion is being exchanged.
- (ii) is an example of a double displacement reaction because both of the reacting compounds are exchanging ions.
- (iii) is an example of combination reaction because two substances are combining to form a single product.
- (iv) is a redox reaction where CH 4 is getting oxidized and O 2 is getting reduced.
So, the correct answer is (b) (ii) only