Example 9 - Find all zeroes of 2x4 - 3x3 - 3x2 + 6x - 2 - Examples

Example 9 - Chapter 2 Class 10 Polynomials - Part 2

Example 9 - Chapter 2 Class 10 Polynomials - Part 3
Example 9 - Chapter 2 Class 10 Polynomials - Part 4

Go Ad-free

Transcript

Example 9 (Introduction) Find all the zeroes of 2x4 – 3x3 – 3x2 + 6x – 2, if you know that two of its zeroes are √2 and − √2 . 2 is a factor of 6 3 is a factor of 6 So, 2 × 3 is also a factor of 6 We will use the same in our question Example 9 Find all the zeroes of 2x4 – 3x3 – 3x2 + 6x – 2, if you know that two of its zeroes are √2 and − √2 . Let p(x) = 2𝑥4−3𝑥3−3𝑥2+6𝑥 −2 Since x = √2 is a zero , x – √2 is a factor Since x = – √2 is a zero , x + √2 is a factor Hence , (x + √2) (x - √2) is a factor i.e. (x2 – (√2)^2) is also a factor i.e. (x2 – 2) is also a factor Now by dividing the given polynomial by (x2 – 2) We can find out other factors Now, we factorize 2x2 – 3x + 1 2x2 – 3x + 1 We use splitting the middle term method = 2x2 – 2x – x + 1 = 2x(x – 1) – 1 (x – 1) = (2x – 1)(x – 1) ∴ x = 1/2 & x = 1 are zero of p(x) Therefore, the zeroes of p(x) are √2, –√2, 1/2, and 1.

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo