Question 2 - Division algorithm - Chapter 2 Class 10 Polynomials

Last updated at April 16, 2024 by

Example 7 - Divide 3x3 + x2 + 2x + 5 by 1 + 2x + x2 - Examples

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Example 7 Divide 3x3 + x2 + 2x + 5 by 1 + 2x + x2. We follow these steps 1. Since we have 3x3, we multiply by 3x 2. Thus, the remainder will be difference of 3x3 + x2 + 2x and 3x3 + 6x2 + 3x 3. Which comes out to be -5x2 - x 4. Now, we have -5x2, so we multiply with -5 5. So, the remainder will be difference of -5x2 - x + 5 and -5x2 -10x - 5 6. Which comes out to be 9x + 10 Therefore, Quotient = 3x – 5 Remainder = 9x + 10

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo