Given that sin π = a/b, then tan π is equal to
(a) b/√(a 2 + b 2 ) (b) b/√(b 2 - a 2 ) (c) a/√(a 2 + b 2 ) (d) b/√(b^ 2 + a 2 )
CBSE Class 10 Sample Paper for 2022 Boards - Maths Basic [MCQ]
CBSE Class 10 Sample Paper for 2022 Boards - Maths Basic [MCQ]
Last updated at Dec. 16, 2024 by Teachoo
Transcript
Question 26 Given that sin π = π/π, then tan π is equal to (a) π/β(π^2 + π^2 ) (b) π/β(π^2 β π^2 ) (c) π/β(π^2 + π^2 ) (d) π/β(π^2 + π^2 ) Let Ξ ABC be the right angled triangle Given sin π = π/π Since sin π = πΆπππππππ/π―πππππππππ Therefore, BC = a, AC = b Finding side AB By Pythagoras theorem AC2 = AB2 + BC2 b2 = AB2 + a2 b2 β a2 = AB2 AB2 = b2 β a2 AB = β(π^πβπ^π ) Now, tan π = π΅πΆ/π΄π΅ = π/β(π^π β π^π ) So, the correct answer is (d)