Point P divides the line segment joining R (βˆ’1, 3) and S (9, 8) in ratio k:1. If P lies on the line x – y + 2 = 0, then value of k is
(a) 2/3Β  (b) 1/2 Β  (c) 1/3Β  Β  (d) 1/4

Ques 35 (MCQ) - Point P divides line segment joining R(-1, 3), S(9,8) - CBSE Class 10 Sample Paper for 2022 Boards - Maths Standard [MCQ]

part 2 - Question 35 - CBSE Class 10 Sample Paper for 2022 Boards - Maths Standard [MCQ] - Solutions of Sample Papers for Class 10 Boards - Class 10
part 3 - Question 35 - CBSE Class 10 Sample Paper for 2022 Boards - Maths Standard [MCQ] - Solutions of Sample Papers for Class 10 Boards - Class 10

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Question 35 Point P divides the line segment joining R (βˆ’1, 3) and S (9, 8) in ratio k:1. If P lies on the line x – y + 2 = 0, then value of k is (a) 2/3 (b) 1/2 (c) 1/3 (d) 1/4 Using section formula x = (π’ŽπŸ π’™πŸ + π’ŽπŸ π’™πŸ)/(π’ŽπŸ + π’ŽπŸ) x = (π‘˜ Γ— 9 + 1 Γ— (βˆ’1))/(π‘˜ + 1) x = (πŸ—π’Œ βˆ’ 𝟏)/(π’Œ + 𝟏) y = (π’ŽπŸ π’šπŸ + π’ŽπŸ π’šπŸ)/(π’ŽπŸ + π’ŽπŸ) y = (π‘˜ Γ— 8 + 1 Γ— 3)/(π‘˜ + 1) y = (πŸ–π’Œ + πŸ‘)/(π’Œ + 𝟏) Since point P lies on line It will satisfy it’s equation Putting values of x and y in equation x βˆ’ y + 2 = 0 (πŸ—π’Œ βˆ’ 𝟏)/(π’Œ + 𝟏)βˆ’(πŸ–π’Œ + πŸ‘)/(π’Œ + 𝟏) + 2 = 0 ((9π‘˜ βˆ’1) βˆ’ (8π‘˜ + 3))/(π‘˜ + 1) + 2 = 0 (9π‘˜ βˆ’ 1 βˆ’ 8π‘˜ βˆ’ 3)/(π‘˜ + 1) + 2 = 0 (π‘˜ βˆ’ 4)/(π‘˜ + 1) + 2 = 0 (π‘˜ βˆ’ 4 + 2(π‘˜ + 1))/(π‘˜ + 1) = 0 (πŸ‘π’Œ βˆ’ 𝟐)/(π’Œ + 𝟏) = 0 3k βˆ’ 2 = 0 3k = 2 k = 𝟐/πŸ‘ So, the correct answer is (a)

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo