CBSE Class 10 Sample Paper for 2022 Boards - Maths Standard [MCQ]
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CBSE Class 10 Sample Paper for 2022 Boards - Maths Standard [MCQ]
Last updated at Dec. 16, 2024 by Teachoo
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This question is inspired from Ex 7.2, 6 (NCERT) - Chapter 7 Class 10 - Coordinate Geometry
![Ques 29 (MCQ) - The vertices of a parallelogram are A(1,2), B(4, y), - CBSE Class 10 Sample Paper for 2022 Boards - Maths Standard [MCQ]](https://cdn.teachoo.com/7d78acc4-38f6-4257-9347-de2700a7a084/slide59.jpeg)
![part 2 - Question 29 - CBSE Class 10 Sample Paper for 2022 Boards - Maths Standard [MCQ] - Solutions of Sample Papers for Class 10 Boards - Class 10](https://cdn.teachoo.com/3a2fa8b0-de59-4a12-90e3-47b5c552e855/slide60.jpeg)
![part 3 - Question 29 - CBSE Class 10 Sample Paper for 2022 Boards - Maths Standard [MCQ] - Solutions of Sample Papers for Class 10 Boards - Class 10](https://cdn.teachoo.com/5814bed2-80d0-4596-87c0-600dbefbbc47/slide61.jpeg)
Transcript
Question 29 The vertices of a parallelogram in order are A (1, 2), B (4, y), C (x, 6) and D (3, 5). Then (x, y) is (a) (6, 3) (b) (3, 6) (c) (5, 6) (d) (1, 4) Given A(1, 2), B(4, y), C(x, 6), D(3, 5) We know that Diagonals of parallelogram bisect each other So, O is the midβpoint of AC & BD Finding midβpoint of AC Coordinates of O = ((1 + π₯)/2,(2 + 6)/2) = ((1 + π₯)/2,8/2) = ((π + π)/π,π) Finding midβpoint of BD Coordinates of O = ((3 + 4)/2,(5 + π¦)/2) = (π/π,(5 + π¦)/2) Now, ((π + π)/π,π) = (π/π,(5 + π¦)/2) Comparing x-coordinate (1 + π₯)/2 = 7/2 (1 + x) = 7 x = 7 β 1 x = 6 Comparing x-coordinate 4 = (π¦ + 5)/2 4 Γ 2 = y + 5 8 β 5 = y y = 3 β΄ (x, y) = (6, 3) So, the correct answer is (a)
