If 4 tan β = 3, then (4 sin⁡β  - 3 cos⁡β)/(4 sin⁡β  + 3 cos⁡β ) =

(a) 0  (b) 1/3      (c) 2/3        (d) 3/4 

 

This question is inspired from Question 15 - NCERT Exemplar - MCQ - Chapter 8 Class 10 - Introduction to Trignometry

 

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Question 18 If 4 tan β = 3, then (4 sin⁡𝛽 − 3 cos⁡𝛽)/(4 sin⁡𝛽 + 3 cos⁡𝛽 ) = (a) 0 (b) 1/3 (c) 2/3 (d) 3/4 Given 4 tan β = 3 tan β = 𝟑/𝟒 Now, (4 sin⁡〖𝛽 − 3 cos⁡𝛽 〗)/(4 sin⁡〖𝛽 + 〖3 cos〗⁡𝛽 〗 ) Dividing numerator and denominator by cos θ = (4 sin⁡𝛽/cos⁡𝛽 − 3 cos⁡𝛽/cos⁡𝛽 )/(4 sin⁡𝛽/cos⁡𝛽 + 3 cos⁡𝛽/cos⁡𝛽 ) = (𝟒 𝐭𝐚𝐧⁡〖𝛽 − 𝟑〗)/(𝟒 𝐭𝐚𝐧⁡〖𝜽 + 𝟑〗 ) Putting tan 𝛽 = 𝟑/𝟒 = (4 × 3/4 − 3)/(4 × 3/4 + 3) = (3 − 3)/(3 + 3) = 0/6 = 0 So, the correct answer is (a)

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo