If tan −1 x = y, then:
(a) −1 < y < 1 (b) (-π)/2 ≤ y ≤ π/2
(c) (-π)/2 < y < π/2 (d) y ∈ {(-π)/2,π/2}
CBSE Class 12 Sample Paper for 2022 Boards (MCQ Based - for Term 1)
CBSE Class 12 Sample Paper for 2022 Boards (MCQ Based - for Term 1)
Last updated at Dec. 16, 2024 by Teachoo
Transcript
Question 36 If tanβ1 x = y, then: (a) β1 < y < 1 (b) (βπ)/2 β€ y β€ π/2 (c) (βπ)/2 < y < π/2 (d) y β {(βπ)/2,π/2}y = tanβ1 x We know that tan x is not defined at x = (βπ)/2, and x = π/2 Thus, Range of tanβ1 π₯ excludes (βπ)/2 and π/2 So, the correct answer is (C)