if e x + e y =e (x+y) , then dy/dx is :
(a) e
(y-x)
(b) e
(x+y)
(c) -e
(y-x)
(d) 2 e
(x-y)


CBSE Class 12 Sample Paper for 2022 Boards (MCQ Based - for Term 1)
CBSE Class 12 Sample Paper for 2022 Boards (MCQ Based - for Term 1)
Last updated at Dec. 16, 2024 by Teachoo
Transcript
Question 12 if ๐^๐ฅ+ ๐^๐ฆ=๐^(๐ฅ+๐ฆ), ๐กโ๐๐ ๐๐ฆ/๐๐ฅ is : (a) ๐^(๐ฆโ๐ฅ) (b) ๐^(๐ฅ+๐ฆ) (c) ใโ๐ใ^(๐ฆโ๐ฅ) (d) 2 ๐^(๐ฅโ๐ฆ) Given ๐^๐ฅ+๐^๐ฆ=๐^(๐ฅ + ๐ฆ) ๐^๐ฅ+๐^๐ฆ=๐^๐ฅ.๐^๐ฆ Dividing by ๐^๐.๐^๐ both sides ๐^๐/(๐^๐ ๐^๐ )+๐^๐/(๐^๐ ๐^๐ )=(๐^๐ ๐^๐)/(๐^๐ ๐^๐ ) 1/๐^๐ฆ +1/๐^๐ฅ =1 ๐^(โ๐)+๐^(โ๐)=๐ Differentiating both sides w.r.t x ๐ (๐^(โ๐) )/๐ ๐+๐ (๐^(โ๐) )/๐ ๐=๐ (๐)/๐ ๐ ๐^(โ๐).(๐ (โ๐))/๐ ๐โ๐^(โ๐)=๐ โ๐^(โ๐ฆ).๐๐ฆ/๐๐ฅโ๐^(โ๐ฅ)=0 โ๐^(โ๐ฆ).๐๐ฆ/๐๐ฅ=๐^(โ๐ฅ) ๐ ๐/๐ ๐=๐^(โ๐)/(โ๐^(โ๐) ) ๐๐ฆ/๐๐ฅ=โ๐^(โ๐ฅโ(โ๐ฆ)) ๐๐ฆ/๐๐ฅ=โ๐^(โ๐ฅ + ๐ฆ) ๐ ๐/๐ ๐=โ๐^(๐ โ ๐) So, the correct answer is (c)